1/(x+7)^2+4/(x+7)+4=0

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Solution for 1/(x+7)^2+4/(x+7)+4=0 equation: 



1/(x+7)^2+4/(x+7)+4=0



Domain of the equation: (x+7)^2!=0

x∈R





Domain of the equation: (x+7)!=0

We move all terms containing x to the left, all other terms to the right

x!=-7

x∈R



We calculate fractions


(1*(x+7))/((x+7)^2*(x+7))+(4*(x+7)^2)/((x+7)^2*(x+7))+4=0



We calculate terms in parentheses: +(1*(x+7))/((x+7)^2*(x+7)), so:

1*(x+7))/((x+7)^2*(x+7)

We multiply all the terms by the denominator


1*(x+7))

Back to the equation:

+(1*(x+7)))





We calculate terms in parentheses: +(4*(x+7)^2)/((x+7)^2*(x+7)), so:

4*(x+7)^2)/((x+7)^2*(x+7)

We multiply all the terms by the denominator


4*(x+7)^2)

We multiply parentheses

4x+

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)

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